1. If a man purchases 11 balls for Rs 10 and sells 10 balls for Rs. 11 , How much profit or loss does he make ?
Solution:
Cost price of one ball = 10 / 11 ,
Selling Price of one ball 11 / 10
10/11*110=100
11/10*110 =121
--------
21%
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(or)
Cost price of one ball = 10 / 11 ,
Selling Price of one ball 11 / 10
So % profit or loss will be
= [( 11 / 10 - 10 / 11 ) / 10 / 11 ] * 100
= 21 %
2. A dealer sell its rice at cost price, but uses its weight 900 gm for kg. Find hig gain percentage.
Solution :
% Gain = [ True Weight - False Weight ] / False Weight
Gain % = [ ( 1000 - 900 ) / 900 ] * 100
= 1 * 100 / 9
= 11 . 11 %
3. A seller uses 900 gm in place of one kg to sell his goods. Find his actual % profit or loss When he sells his articles at 5 % loss on cost price ?
Solution :
[100 - X] Z/Y -100
= [100 - 5] 1000/900 -100
= 5.56%
4. A seller uses 900 gm in place of one kg to sell his goods. Find his actual % profit or loss When he sells his articles at 5 % profit on cost price ?
Solution :
[100 + X] Z/Y -100
=(100+5)1000/900 -100
= 16.67%
5. A grocer allows a discount of 8 % . How much % above cost price he must mark his goods to make a profit of 12 % ?
Solution :
X - 8 -8X/100 =12
so, x=21.73%
6. If A sells a good to B at profit of 15 %, B sells it to C at a profit of 20 %. If 300 Rs. is paid by C then what was the cost price for A?
Solution :
CP of A
=[ 100 / (100+15) ] * [ 100 / (100+20) ] *300
=217.40
7. If A sells a good to B at profit of 15 %, B sells it to C at a profit of 20 %. What is the resultant profit and loss ?
Solution:
[ 15+20+ (15*20 /100) ]
=38%
8. By selling a shirt at price 500 a trader get loss of 10 %. At what price he must sell the shirt in order to get 5 % of profit ?
Solution :
Use the formula of Goods Passing through successive hands,
here for loss x will be -10 %
90% = 500
105% = x
x= [ (500*105)/90 ]
=583.3
9. Rakesh buys a scooter worth Rs. 10,000. He sells it to Mohan at a profit of 10%. If after sometime Mohan sells it back to Rakesh at a loss of 10%, then totally:
a) Rakesh loses Rs. 100
b) Rakesh loses Rs. 1100
c) Rakesh gains Rs. 100
d) Rakesh gains Rs. 1100
Solution :
cost price of the scooter= 10000
sp of scooter@ 10% gain=11000
again , now sp price given so the cost price @loss of 10%=9900
now profit= 1100 (since sp-cp)=profit so gain of 1100.
10. Prabodh bought 30 kg of rice at the rate of Rs. 8.50 per kg and 20 kg of rice at the rate of Rs. 9.00 per kg. He mixed the two. At what price (App.) per kg should he sell the mixture in order to get 20% profit?
a) Rs. 9.50
b) Rs. 8.50
c) Rs. 10.50
d) Rs. 12.00
Solution:
let cp of mix be x.
30/20=(9-x)/(x-8.5)
solving this x=8.7
now sp= 20 % of 8.7
which is equal to 10.44 =(10.5) approx.
11. A, B, C started a business with their investments in the ratio 1:3:5. After 4 months, A invested the same amount as before and B as well as C withdrew half of their investments. The ratio of their profits at the end of the year is:
a) 4:3:5
b) 5:6:10
c) 6:5:10
d) 10:5:6
Solution:
ratio for first four months=1:3:5
for last 8 months ratio is=2:3/2:5/2
profit ratio at end of year
=1*4+2*8:3*4+3/2*8:5*4+5/2*8
20:24:40
5:6:10 is answer
12. A man bought a number of clips at 3 for a rupee and an equal number at 2 for a rupee. At what price per dozen should he sell them to make a profit of 20% ?
a) Rs 4
b) Rs 5
c) Rs 6
d) Rs 7
Solution:
Lets assume a dozen of clips were brought at 3 for a rupee and another dozen of clips were brought at 2 for a rupee
total CP for 1 dozen in which the cost is 3 for a rupee= 12/3 =4
total CP for 1 dozen in which the cost is 2 for a rupee= 12/2 = 6
total cp for 2 dozens = 6+4 = 10
percentage profit = 20% on Rs. 10 = 20/100 * 10 = Rs.2
After percentage profit the SP of 2 dozen is
Profit = SP - CP
SP = Profit + CP
SP = 2+ 10 = 12
SP of 1 dozen = 12/2 = 6
13. A sells a bicycle to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays Rs. 225 for it, the cost price of the bicycle for A is:
a) Rs. 110
b) Rs. 120
c) Rs. 125
d) Rs. 150
Solution:
Let cost price for A = Rs. 100.
SP for A = CP for
B = 100 + 20% of 100 = 120.
SP for B = CP for
C = 120 + 25% of 120 = 150.
Given,
CP for C = 225
So,
150 = 225
1 = 225/150
100 = (225 *100)/150 = Rs. 150.
CP for A = Rs. 150.
14. Naresh purchased a TV set for Rs11,250 after getting discount of 10% on the labeled price. He spent Rs150 on transport and Rs800 on installation. At what price should it be sold so that the profit earned would be 15% if no discount was offered?
1) Rs12,937.50
2) Rs14,030
3) Rs13,450
4) Rs15,467.50
5) None of these
Solution:
Let original price was X.
X - 10% of X = 11,250
X - X/10 = 11, 250
9X/10 = 11, 250
9X = 112500
X = 12500.
Total expences,
12500 + 150 + 800 = 13,450.
Selling Price with 15% profit,
= 13450 + 15% of 13450
= Rs. 15467.50
15. Manoj sold an article for Rs15,000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price?
1) Rs12,500
2) Rs13,500
3) Rs12,250
4) Rs13,250
5) None of these
Solution:
S.P. after 10% discount
= 15000-10%of 15000
= 15000-1500= Rs. 13500
Profit on S.P. = 8%
C.P.= 13500⁄108 ×100= Rs. 12500
16. If Ramu buys books at 11 books for Rs10 and sells at 10 books for Rs12, then what will be his gain percent?
1) 11%
2) 22%
3) 32%
4)15%
5) None of these
Solution:
85 : 9 = 105 : x
x = [9 × 105/80]
= Rs.11.81
Hence, S.P. per kg= Rs.11.81
11 10
10 12
(cross multiply)
(11*12-10*10)/10*10
32%
17. A watch was sold at a loss of 9%. It was observed that if the selling price was Rs420 more, the profit made would have been 5%. What is the actual selling price of the watch?
1) Rs2700
2) Rs2730
3) Rs3270
4) Rs3000
Solution:
We can solve it directly by formula:
S.P1/100-L%=S.P2/100+P%
where + or - is depends on it is P% or L%
So,
S.p1/91 = S.P1+420/105
on solving it we get,
S.P1=2730
18. .After selling a book, Rohan found that he had made a loss of 12%. He also found that had he sold it for Rs36 more, he would have made a profit of 6%. What was the initial loss?
1) Rs12
2) Rs18
3) Rs20
4) Data inadequate
5) None of these
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